How to get the user name of a process when Vista UAC open?

External Since: Apr 29, 2007 Posts: 2

I can get the user name of a process in Windows XP by following code:
GetCurrentProcess();
GetSecurityInfo(handle,SE_KERNEL_OBJECT,OWNER_SECURITY_INFORMATION,&pSidOwner,NULL,NULL,NULL,&pSD);LookupAccountSid(NULL, pSidOwner, lpName,&cchName,lpReferencedDomainName,&cchReferencedDomainName, &peUse);But I failed in Vista when UAC opened:if the user of the process is in administrators group, and it is run asadministrator, the code above return the name (in lpName): "administrators"instead of the real user name.Who can help me?

External Since: Sep 01, 2005 Posts: 45

"Steff" <st_10.DeleteThis@hotmail.com> wrote in message
news:u5TIRPkiHHA.4772@TK2MSFTNGP04.phx.gbl...
>I can get the user name of a process in Windows XP by following code:
> GetCurrentProcess();
> GetSecurityInfo(handle,SE_KERNEL_OBJECT,OWNER_SECURITY_INFORMATION,&pSidOwner,NULL,NULL,NULL,&pSD);LookupAccountSid(NULL,
> pSidOwner,
> lpName,&cchName,lpReferencedDomainName,&cchReferencedDomainName,
> &peUse);But I failed in Vista when UAC opened:if the user of the process
> is in administrators group, and it is run asadministrator, the code above
> return the name (in lpName): "administrators"instead of the real user
> name.Who can help me?
>

Sounds like you need to use 'impersonation'

--
Jon