One more C++ cout question

In article <uce-7F9183.05065022032008.DeleteThis@comcast.dca.giganews.com>,
Gregory Weston <uce.DeleteThis@splook.com> wrote:

> In article <qcneb5-7m7.ln1.DeleteThis@Hedley.internal.thethurmans.com>,
> Can I Get a Word In <lorenzo.DeleteThis@diespammerhurmans.com> wrote:
>
> > I have a hex value, 0x14000, and I want to output it as, 0x00014000. Is
> > it possible to get this output using std::cout?
> > Thanks
>
> #include <iostream>
> using namespace std;
> int main(int argc, const char* argv[])
> {
> cout << "0x";
> cout.flags(ios::hex);
> cout.width(;
> cout.fill('0');
> cout << 0x14000 << "\n";
> return 0;
> }

That works, but I prefer to use io manipulators:

#include <iostream>
#include <iomanip>
using std::cout;
using std::setw;
using std::setfill;
using std::ios;
using std::hex;
using std::dec;

int main(int argc, char * const argv[]) {

cout << " 0x" << setw( << setfill('0') << hex << 0x14000 << "\n" << dec << 123 << "\n";

return 0;
}

In article <oster-7139AB.08280222032008.RemoveThis@newsclstr02.news.prodigy.com>,
David Phillip Oster <oster.RemoveThis@ieee.org> wrote:

> In article <uce-7F9183.05065022032008.RemoveThis@comcast.dca.giganews.com>,
> Gregory Weston <uce.RemoveThis@splook.com> wrote:
>
> > In article <qcneb5-7m7.ln1.RemoveThis@Hedley.internal.thethurmans.com>,
> > Can I Get a Word In <lorenzo.RemoveThis@diespammerhurmans.com> wrote:
> >
> > > I have a hex value, 0x14000, and I want to output it as, 0x00014000. Is
> > > it possible to get this output using std::cout?
> > > Thanks
> >
> > #include <iostream>
> > using namespace std;
> > int main(int argc, const char* argv[])
> > {
> > cout << "0x";
> > cout.flags(ios::hex);
> > cout.width(;
> > cout.fill('0');
> > cout << 0x14000 << "\n";
> > return 0;
> > }
>
> That works, but I prefer to use io manipulators:
>
> #include <iostream>
> #include <iomanip>
> using std::cout;
> using std::setw;
> using std::setfill;
> using std::ios;
> using std::hex;
> using std::dec;
>
> int main(int argc, char * const argv[]) {
>
> cout << " 0x" << setw( << setfill('0') << hex << 0x14000 << "\n" << dec
> << 123 << "\n";
>
> return 0;
> }

Certainly a more elegant solution, but I figured the question was basic
enough that it kind of warranted the most explicit/obvious possible
answer. I've found manipulators confuse people completely new to the
language more than they help right up front.

Gregory Weston wrote:
> In article <oster-7139AB.08280222032008.RemoveThis@newsclstr02.news.prodigy.com>,
> David Phillip Oster <oster.RemoveThis@ieee.org> wrote:
>
>> In article <uce-7F9183.05065022032008.RemoveThis@comcast.dca.giganews.com>,
>> Gregory Weston <uce.RemoveThis@splook.com> wrote:
>>
>>> In article <qcneb5-7m7.ln1.RemoveThis@Hedley.internal.thethurmans.com>,
>>> Can I Get a Word In <lorenzo.RemoveThis@diespammerhurmans.com> wrote:
>>>
>>>> I have a hex value, 0x14000, and I want to output it as, 0x00014000. Is
>>>> it possible to get this output using std::cout?
>>>> Thanks
>>> #include <iostream>
>>> using namespace std;
>>> int main(int argc, const char* argv[])
>>> {
>>> cout << "0x";
>>> cout.flags(ios::hex);
>>> cout.width(;
>>> cout.fill('0');
>>> cout << 0x14000 << "\n";
>>> return 0;
>>> }
>> That works, but I prefer to use io manipulators:
>>
>> #include <iostream>
>> #include <iomanip>
>> using std::cout;
>> using std::setw;
>> using std::setfill;
>> using std::ios;
>> using std::hex;
>> using std::dec;
>>
>> int main(int argc, char * const argv[]) {
>>
>> cout << " 0x" << setw( << setfill('0') << hex << 0x14000 << "\n" << dec
>> << 123 << "\n";
>>
>> return 0;
>> }
>
> Certainly a more elegant solution, but I figured the question was basic
> enough that it kind of warranted the most explicit/obvious possible
> answer. I've found manipulators confuse people completely new to the
> language more than they help right up front.
Thanks for the reply. I'm actually comfortable using manipulators, it
just wasn't immediately obvious how to use them to get the output I wanted.

David Phillip Oster wrote:
> In article <uce-7F9183.05065022032008.TakeThisOut@comcast.dca.giganews.com>,
> Gregory Weston <uce.TakeThisOut@splook.com> wrote:
>
>> In article <qcneb5-7m7.ln1.TakeThisOut@Hedley.internal.thethurmans.com>,
>> Can I Get a Word In <lorenzo.TakeThisOut@diespammerhurmans.com> wrote:
>>
>>> I have a hex value, 0x14000, and I want to output it as, 0x00014000. Is
>>> it possible to get this output using std::cout?
>>> Thanks
>> #include <iostream>
>> using namespace std;
>> int main(int argc, const char* argv[])
>> {
>> cout << "0x";
>> cout.flags(ios::hex);
>> cout.width(;
>> cout.fill('0');
>> cout << 0x14000 << "\n";
>> return 0;
>> }
>
> That works, but I prefer to use io manipulators:
>
> #include <iostream>
> #include <iomanip>
> using std::cout;
> using std::setw;
> using std::setfill;
> using std::ios;
> using std::hex;
> using std::dec;
>
> int main(int argc, char * const argv[]) {
>
> cout << " 0x" << setw( << setfill('0') << hex << 0x14000 << "\n" << dec << 123 << "\n";
>
> return 0;
> }
Thanks, I got it.