<rogacasa.RemoveThis@gmail.com> wrote:
> Hi. I'm really interested in this mobile drive, which is actually a
> RAID 0 configuration, from G-Technology:
>
> http://www.g-technology.com/Products/G-RAID-mini.cfm
>
> I really like this idea, but I'm a little worried about running it on
> FireWire bus power. I'm not worried about battery drainage -- I'm
> worried about the current draw frying my FireWire 800 port. This
> little device has two 7200RPM 2.5" SATA drives in it, PLUS a fan. It
> can be bus powered, which I like, and that is why I am interested in
> it. But doesn't 2 drives and a fan seem like a little much to be
> trying to run off bus power?
>
> The G-technology website does not say what the current draw of this
> drive is.
>
> Does anyone know the maximum allowable current draw for the Firewire
> 800 spec?
According to <http://en.wikipedia.org/wiki/Firewire>, the maximum power
which can be carried over a Firewire cable is about 45 watts at 30
volts.
The actual wattage and voltage will vary depending on the computer or
other power sources connected to the bus, and the current would vary
accordingly.
Apple's developer notes for each Mac model specify the power they can
supply via the Firewire ports, and it is typically in the order of 6 to
8 watts per port, and I expect the voltage is typically in the order of
12 to 24V (it may be unregulated). Some models may have some
flexibility, e.g. if you have three Firewire ports you might be able to
get away with one power hungry device (in the order of 18W) as long as
you don't try to draw much current from the other two ports.
There is likely to be a current limiting device in the Mac which will
switch off the Firewire power output if the device draws too much power.
You might be able to get a rough idea of the current consumption of the
device by looking for specifications for 7200 RPM 2.5" SATA drives and
seeing what their maximum (turn-on) surge current is on the 12V rail,
combined with their 5V current, then allow some headroom for each
figure. To get a power figure, multiply the voltage and current and then
add them together.
Converting that to an estimate of power drawn from Firewire is
difficult, as it depends on the efficiency of the device's internal
power supply. Assume 50% for argument's sake, i.e. double the wattage
figure from the calculation above.
--
David Empson
dempson.RemoveThis@actrix.gen.nz