electing multiple people

Hi,

During the discussion on the proposed social committee, I proposed that we
elect (all) the members of that committee. The Debian Constitution currently
doesn't provide for a way to do so - it only describes how a single winner
is decided.

So, I proposed the following addition to the section A.6. Vote Counting
(part of appendix A Standard Resolution Procedure):

+ If the election requires multiple winners, the list of winners is
+ created by sorting the list of options by ascending strength.
+ If there are multiple winners with the same ranking which exceed
+ the desired length of the list, the length of the list is extended
+ to include the entire last set of multiple winners.

Is this technically sound? I don't know voting method syntax.

[I posted this on -project, but nobody really commented on it, that's why
I'm re-posting to -vote.]

By "sorting the list of options by ascending strength" I refer to that list
we get from the beat matrix, such as in:

http://www.debian.org/vote/2007/vote_001#outcome

If for example in that outcome we wanted to pick four candidates, it
seems to me that they would be Hocever, McIntyre, Herzog, Verhelst.
If for example we wanted to pick seven, we couldn't go past the first six.

In that graph, no two options happened to be at the same horizontal level.
If by any chance we got that situation, my ammendment further stated:

+ If there are multiple winners with the same ranking which exceed
+ the desired length of the list, the length of the list is extended
+ to include the entire last set of multiple winners.

I thought that that made sense. Does it?

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On 08/10/07 at 17:33 +0200, Josip Rodin wrote:
> Hi,
>
> During the discussion on the proposed social committee, I proposed that we
> elect (all) the members of that committee. The Debian Constitution currently
> doesn't provide for a way to do so - it only describes how a single winner
> is decided.
>
> So, I proposed the following addition to the section A.6. Vote Counting
> (part of appendix A Standard Resolution Procedure):
>
> + If the election requires multiple winners, the list of winners is
> + created by sorting the list of options by ascending strength.
> + If there are multiple winners with the same ranking which exceed
> + the desired length of the list, the length of the list is extended
> + to include the entire last set of multiple winners.
>
> Is this technically sound? I don't know voting method syntax.

couldn't we get cycles using that? Alternatively, we could iteratively
elect:
- winner1: the winner with all candidates
- winner2: the winner with all candidates minus winner1
- winner3: the winner with all candidates minus [winner1, winner2]
- etc
using the same tally sheet

Or, we could elect a list directly (ie each option is a list of people
willing to work together as SC), which would allow to elect a SC which
is actually representative for Debian. It's probably better than the
first solution, as the first solution isn't clone-proof: we could have
elected n Sams!!
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| Lucas Nussbaum
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